1/.
8,4 g
C-C-C=C-C-C + [O] + H2O --> C-C-C(OH)-C(OH)-C-C/.5
5x84
n moli
2KMnO4 + 3H2SO4 --> K2SO4 + 2MnSO4 + 3H2O + 5[O]/.1
2
n = 8,4x2/5x84 = 0,04 moli KMnO4
Cm = n/Vs, Vs = n/Cm = 0,04/0,2 = 0.2 L sol KMno4
2/.
CnH2n + Br2 --CCl4--> CnH2nBr2
la alchena avem 2nx100/14n = 14,28%
la compusul bromurat , procentul de H va fi
14,28 - 9,93 = 4,355%
100% ........................... 4,355% H
14n+160 .................... 2n
=> 200n = 60,97n + 696,8
=> n = 5 => C5H10 , pentena