Răspuns:
Explicație:
CaCO3
-se afla masa molara
M=ACa + AC + 3AO
=40 + 12 +3.16
=100 -----> 1mol=100g ( 100g/moli )
-se aplica relatia : n = m : M ; in care n= nr. moli ; m=masa de subst. ( g )
M=masa molara ( g/moli )
n=m : M
n= 300g : 100g/moli=3 moli CaCO3
NaOH - hidroxid de natriu ( soda caustica )
M= ANa + AO + AH
=23+16 +1
=40------> 40g/moli
n=m : M
m=n . M
m= 4moli .40g/moli=160 g NaOH