Răspuns:
M,NaOH= 40g/mol M,Cu(OH)2= 98g/mol M,NaCl=58,5g/mol
2mol.............................1mol........................1mol sau,in grame
2NaOH + CuCl2------> Cu(OH)2↓ +2NaCl
2x40g..................................98g.................2x58,5g
120g......................................x.....................y
x= 98x120/80 gCu(OH)2=............................
y= 2x58,5x120/80 gNaCl=.................................
finalizeaza calculele !!!!
Explicație: