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Se stie ca a=11 si b+c=8.Calculati:
h) 3*a-3*b-3*c



Răspuns :

3·a–3·b–3·c=

=3(a–b–c)=

=3(11–b–c)

–b–c=–(b+c)

=3(118)=

=3·3=9