Exercitiul 49? Va rog
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Răspuns:
calculez moli trinitrat de glicerina, stiind M= 227kg/kmol
niu=m/M= 13,62kg/227kg/kmol= 0,06kmol= 60mol
calculez moli de gaze din ecuatia chimica
4mol....................12mol.........10mol......6mol...1mol
4C3H5O9N3---> 12CO2 + 10H2O + 6N2 + O2
60mol................x=180......y=150.........z=90.......15mol
total moli gaze: niu= 435
calculez volumul lor, in conditiile date, cu ecuatia
pV=niuRT-----> V= 435X0,082X(273+27)L=10701 L=10,7 m³
Explicație: