Răspuns:
Explicație pas cu pas:
a) Ariabazei=12√3 cm², l²·√3 /4 = 12√3 , ⇒l²·√3=4·12√3, ⇒l²=4·12=4·4·3
Deci l=√(4·4·3)=2·2·√3=4√3cm
b) Pbazei=3·l=3·4√3=12√3cm
c) Diagonala fetei laterale =8cm
Dupa T.P. ⇒ m²=8²-l²=64-(4√3)²=64-16·3=64-48=16, deci m=√16=4cm
d) Pf = 2·(l+m)=2·(4√3+4)=2·4·(√3 +1)=8·(√3+1)cm
e) Af=l·m=4√3 ·4=16√3cm²
f) m(∡C'BC)=?
ΔC'BC dreptunghic, m=4, diagonala=8, deci 4=(1/2)·8, ⇒m(∡C'BC)=30°
