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stiind ca a=2, b+c=52 si b-c=50calculati a)a×b+a×c b) a×b-a×c+10​

Răspuns :

a = 2

b + c = 52

b - c = 50

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a ) ab + ac

b ) ab - ac + 10

a ) a ( b + c ) = 2 × 52 = 104

b ) a ( b - c ) + 10 = 2 × 50 + 10 = 110

Răspuns:folosim factorul comun la amandoua punctele

A)a×b+a×c=2×(b+c)=2×52=104

B)a×b-a×c=2×(b-c)=2×50=100