Răspuns:
ω=2π/T
ω=π
π=2π/T T=perioada
1=2/T=>T=2
Deci t=T/4=2/4=1/2 s
y=Asin(π*1/2+π/4)=Asin(π/2+π/4)
y=Asin(3π/4) rel1
Energia potentiala
Ep=m²ω²/2*A²sin ²3π/4
Energia cinetica Ec=m²ω²/2*A²cos²3π/4
Ec/Ep=[m²ω²/2*A²sin²3π/4]/[m²ω²/2*A²cos²3π/4]=dupa simplificare cu m²ω²/2*A²=
sin²3π/4/cos²3π/4=
tg²3π/4=(-1)²=1
Explicație:
