Răspuns:
calculez mas C si masa H , stiind M,C=12g/mol,M,CO2=44g/mol
M,H= 1g/mol M,h2o=18g/mol
44gCO2........12gC
6,6g..............m= 1,8gC
18gH2O..........2gH
3,6g.................m=0,4g
a)calculez compozitia procentuala:
2,2g compus.............1,8gC.................0,4gH
100G..........................x-81,8%C .......y= 18,2%H
deduc formula bruta
niuC= m/M= 81,8/12mol= 6,8molC
niuH= 18,2/1molH=18,2mol
IMPART prin cea mai mica valoare: f.b. CH2,68
DEDUC formula moleculara, stiind masa molara
44= n(12+2,68x1)------> n=3---------> f.m. C3H8 propan
b) CH3-CH2-CH3
c)C3H8+5O2---> 3CO2+4H2O
Explicație:
