Răspuns:
S1-> S2 sol se concentreaza ,fie prin adaugarae de zahar,fie prin evaporarea apei
c1=20%
ms1=500g--------> md1= c1xms1/100= 100g; m,apa1= 500-100=400g
c2= md2x100/ms2= md1x100/(ms1-m,apa), deoarece md2=md1
35/100= 100/(500-m,apa)---> m,apa= 214g
md2=100g ms2= 500-214-> 286g m,apa2= 286-100=186g
S2-->S3 sol. se dilueaza , adaugand apa
c2= 35% md2=100g ms2=286
c3=md3x100/ms3= md2x100/(ms2+m,apa)
25/100= 100/(286+m,apa)......> m,apa= 114g
ms3= 286+114=> 400g, m,d3= md2=100g m,apa3= 400-100g=300g
S3---> S4 se concentreaza , adaugand md zahar
md4=md3+md=100+md g
ms4= ms3+md=400+md
c4/100= md4/ms4
40/100= (100+md)/(400+md) calculeaza md !!!!!
Explicație:
