Răspuns:
Explicație:
196g xg yg
Zn + H2SO4= ZnSO4 + H2
98g 161g 2g
x=196 . 161 : 98=322g g ZnSO4
n=322g : 161g/moli=2 moli ZnSO4
y=196 . 2 : 98= 4 g hidrogen
n=4g : 2g/moli=2moli H2
MH2SO4=2+32+4.16=98---->98g/moli
MZnSO4=65 +32 +4.16=161 ------>161g/moli