Explicație pas cu pas:
V(2x-3)+x=3=>V(2x-3)=3-x =>
2x-3=9-6x+x² => x²-6x+9-2x+3=0 =>
x²-8x+12=0 =>x²-2x-6x+12=0 => x(x-2)-6(x-2)=0=>
(x-2)(x-6)=0 => x1=2 sau x2=6
V(1-x)+V(1+x)=1 =>
1-x+2V(1-x)(1+x)+1+x=1 =>
2+2V(1-x)(1+x)=1 => 2V(1-x)(1+x)=-1 Fals pt ca Vx>=0
=>xۯ