Cum calculez suma? ...................
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Răspuns:
Explicație pas cu pas:
Ai facut foarte bine pana la un moment... ce simplificare defectuoasa ai ??? :))
[tex]log_{2}\frac{1}{2}+log_{2}\frac{2}{3} +log_{2}\frac{3}{4}+...+log_{2}\frac{62}{63} +log_{2}\frac{63}{64}= log_{2}(\frac{1}{2}*\frac{2}{3}*\frac{3}{4}*...*\frac{62}{63}*\frac{63}{64})=log_{2}\frac{1}{64}=log_{2}\frac{1}{2^{6}}=log_{2}2^{-6}=-6*log_{2}2=-6*1=-6[/tex]