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aflati x,y,z daca x supra 3 = y supra 6 ,y supra 2 = z si x + 2y + z = 18 ​

Răspuns :

Răspuns:

[tex] \frac{x}{3} = \frac{y}{6} = > 6x = 3y = > 6 \times 3 = 3 \times 6 = > x = 3 \: \: y = 6.[/tex]

[tex] \frac{y}{2} = z = > z = \frac{6}{2} = 3.[/tex]

[tex]x + 2y + z = 18 = > 3 + 2 \times 6 + 3 = 18 = > 3 + 12 + 3 = 18 = > 18 = 18.[/tex]