Răspuns:
Explicație:
1.
n= m: M
MCa(OH )2= 40 + 2.16 +2=74----->74g/moli
n=296g : 74g/moli= 4moli Ca(OH )2
MH2SO4=2 + 32 +4.16=98------->98g/moli
n= 490g : 98g/moli=5 moli H2SO4
MHNO3=1+14 +3.16=63------>63g/moli
n=126 g : 63g/moli= 2moli HNO3
MKOH=39 + 16 +1=56------> 56g/moli
n=11,2g : 56g/moli= 0,2 moli KOH
2.
m= n.M
m=10moli . 98g/moli=980g H2SO4
MNaOH=23 +16 +1=40----->40g/moli
m=1,8 moli. 40g/moli=
m=5moli. 74g/moli=
m=2moli. 63g/moli=
MNa2CO3=2.23 + 12+ 3.16=106------>106g/moli
m=7moli . 106g/moli=
MCaO=40 + 16=56------>56g/moli
m=0,5 moli .56g/moli=
calculeaza !