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Indicati amplificarile sau simplificarile pt. a obtine fractia 15/35 plecând de la fractia:3/21 ; 3/7 ; 105/245 ; 1515/3535 ; 9×X+9/21×X+21.Mulțumesc !​

Răspuns :

Amplificări sau simplificări:

[tex]\dfrac{9^{(3} }{21} = \dfrac{^{5)} 3}{7} = \bf \dfrac{15}{35}[/tex]

[tex]\dfrac{^{5)} 3}{7} = \bf \dfrac{15}{35}[/tex]

[tex]\dfrac{105^{(7} }{245} = \bf \dfrac{15}{35}[/tex]

[tex]\dfrac{1515^{(101} }{3535} = \bf \dfrac{15}{35}[/tex]

[tex]\dfrac{9 \times x + 9}{21 \times x + 21} = \dfrac{9 \times (x + 1)^{(x+1} }{21 \times (x + 1)} = \dfrac{9^{(3} }{21} = \dfrac{^{5)} 3}{7} = \bf \dfrac{15}{35}\\[/tex]

[tex]\it \dfrac{^{5)}3}{\ 7}= \dfrac{15}{35};\ \ \ \dfrac{\ 105^{(7}}{245}=\dfrac{15}{35};\ \ \ \dfrac{\ \ 1515^{(101}}{3535}=\dfrac{15}{35};\\ \\ \\ \dfrac{9x+9}{21x+21}=\dfrac{9(x+1)}{21(x+1)}=\dfrac{\ 9^{(3}}{21}=\dfrac{^{5)}3}{\ \ 7}=\dfrac{15}{35}[/tex]