Ambele subpuncte vrg
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Răspuns:
Explicație pas cu pas:
a)
a=2√2(√2-1)+2(√2+1)/√2- | √2-3 |=2√(2·2)-2√2+[2√2(√2+1)]/2-(3-√2)=
2·2-2√2+√2(√2+1)-3+√2=4-2√2+√(2·2)+√2-3+√2=4-2√2+2+√2-3+√2=
4-2√2+2+√2-3+√2=4+2-3=3
a=3
b)
b=√(√3-6)²+3 |√3-3 |+√6(2√2-√6)=| √3-6 |+3(3-√3)+2√(6·2)-√(6·6)=
6-√3+9-3√3+2√12-6=6-√3+9-3√3+4√3-6=15-4√3+4√3-6=9
b=9
Media geometrica a numerelor a si b=√(a·b)=√(3·9)=3√3