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3. Rezolvaţi ecuaţiile în mulţimea numerelor reale: a) 4(x + 2)-3x = -17; d) 32-7(x-5)=3(x - 1); g) 14-8(x+3)=2x; i) 6(x-4)+44= 4(2x+1)+2x; k) 3(x+2)-8=2(4x + 3) - 3x; m) 4(x+5)-5(x+3)=x-5; o) 3(2x + 3)-2(3x + 2) = -3(x + 2) + 2; r) x-15+3(x+1)=5(x-2) + 11; c) 11-3(x+5)=2x + 1; f) 4(x+7)-15= 3x; h) 6(x+3)-4=2x-42; j) 5(2x-3)-4x=3(x-8) +63; 1) 4(3x + 2) + 3(2x + 3) = 7(2x + 5) + 28; n) 2(x + 3)-3(2x + 1) = 8(2x-1)-9; p)-3x+5-4(x-1)=-2(x+1)-24; s) 5(x + 2)-2(2x + 3) = 34-5x. otiind că ecuatiile următoare sunt echiva- b) 6(x+5)-3x = 21; e) 4(x-6) + 2x = 18;​

3 Rezolvaţi Ecuaţiile În Mulţimea Numerelor Reale A 4x 23x 17 D 327x53x 1 G 148x32x I 6x444 42x12x K 3x2824x 3 3x M 4x55x3x5 O 32x 323x 2 3x 2 2 R X153x15x2 11 class=

Răspuns :

Răspuns:

a) \(4(x + 2) - 3x = -17\) daca ceva \- x

\[4x + 8 - 3x = -17\]

\[x = -25\]

d) \(32 - 7(x - 5) = 3(x - 1)\)

\[32 - 7x + 35 = 3x - 3\]

\[10x = 0\]

\[x = 0\]

g) \(14 - 8(x + 3) = 2x\)

\[14 - 8x - 24 = 2x\]

\[-10x = 10\]

\[x = -1\]

i) \(6(x - 4) + 44 = 4(2x + 1) + 2x\)

\[6x - 24 + 44 = 8x + 4 + 2x\]

\[6x + 20 = 10x + 4\]

\[4x = 16\]

\[x = 4\]

k) \(3(x + 2) - 8 = 2(4x + 3) - 3x\)

\[3x + 6 - 8 = 8x + 6 - 3x\]

\[x = 1\]

m) \(4(x + 5) - 5(x + 3) = x - 5\)

\[4x + 20 - 5x - 15 = x - 5\]

\[-x + 5 = x - 5\]

\[2x = 10\]

\[x = 5\]

o) \(3(2x + 3) - 2(3x + 2) = -3(x + 2) + 2\)

\[6x + 9 - 6x - 4 = -3x - 6 + 2\]

\[5 = -3x - 4\]

\[3x = -9\]

\[x = -3\]

r) \(x - 15 + 3(x + 1) = 5(x - 2) + 11\)

\[x - 15 + 3x + 3 = 5x - 10 + 11\]

\[4x - 12 = 5x + 1\]

\[x = -13\]

c) \(11 - 3(x + 5) = 2x + 1\)

\[11 - 3x - 15 = 2x + 1\]

\[-5x = 5\]

\[x = -1\]

f) \(4(x + 7) - 15 = 3x\)

\[4x + 28 - 15 = 3x\]

\[x = -13\]

h) \(6(x + 3) - 4 = 2x - 42\)

\[6x + 18 - 4 = 2x - 42\]

\[4x + 14 = 2x - 42\]

\[2x = -56\]

\[x = -28\]

j) \(5(2x - 3) - 4x = 3(x - 8) + 63\)

\[10x - 15 - 4x = 3x - 24 + 63\]

\[6x - 15 = 3x + 39\]

\[3x = 54\]

\[x = 18\]

1) \(4(3x + 2) + 3(2x + 3) = 7(2x + 5) + 28\)

\[12x + 8 + 6x + 9 = 14x + 35 + 28\]

\[18x + 17 = 14x + 63\]

\[4x = 46\]

\[x = 11.5\]

n) \(2(x + 3) - 3(2x + 1) = 8(2x - 1) - 9\)

\[2x + 6 - 6x - 3 = 16x - 8 - 9\]

\[-4x + 3 = 16x - 17\]

\[20x = 20\]

\[x = 1\]

p) \(-3x + 5 - 4(x - 1) = -2(x + 1) - 24\)

\[-3x + 5 - 4x + 4 = -2x - 2 - 24\]

\[-7x + 9 = -2x - 26\]

\[-5x = -35\]

\[x = 7\]

s) \(5(x + 2) - 2(2x + 3) = 34 - 5x\)

\[5x + 10 - 4x - 6 = 34 - 5x\]

\[x = 6\]

Ecuatiile date sunt corecte, iar solutiile pentru variabila \(x\) sunt furnizate.