Aratati ca sin^2 45 - cos^2 60 = 1/4

[tex]\it sin^245^o-cos^260^2=\bigg(\dfrac{\sqrt2}{2}\bigg)^2-\bigg(\dfrac{1}{2}\bigg)^2=\dfrac{2}{4}-\dfrac{1}{4}=\dfrac{2-1}{4}=\dfrac{1}{4}[/tex]