Ecuația reacției de descompunere:
2 moli x y
CuCO₃ -----> CuO + CO₂
1 mol 1 mol 1 mol
Rezolvare:
[tex]m_{CuCO_3}=248\ g\\M_{CuCO_3}=65+12+3\cdot16=125\ g/mol\\n=\frac{m}{M}=\frac{248}{125}=1.984\ moli\ (\approx2\ moli)\\\\n_{CuO}=x=1.984\ moli\\M_{CuO}=65+16=81\ g/mol\\n=\frac{m}{M}\implies m=n\cdot M=1.984\cdot81=160.7\ g\ CuO\\\\n_{CO_2}=y=1.984\ moli\\M_{CO_2}=12+2\cdot\ 16=12+32=44\ g/mol\\n=\frac{m}{M}\implies m=n\cdot M=1.984\cdot 44=87.3\ g\ CO_2\\\\m_{CuO}+m_{CO_2}=160.7+87.3=248\ g\ (m_{CuCO_3})[/tex]
