v,amoniac pur:
p=v,px100/v,i----> v,p=320x70/100 l=224 l
niu= V/Vm= 224/22,4 mol= 10mol total
10mol 10mol
R1 :C4H9Cl + NH3---> C4H9-NH2+HCl
10mol 10mol
R2: C4H9Cl+C4H9-NH2---> (C4H9)2NH+HCL
R3; C4H9Cl+(C4H9)2NH --->(C4H9)3N+HCL
C,u= 70=moli(R2)x100/mol total------mol(R2)=70x10/100= 7
rezulta 7 mol diizobutil amina-->m= niu,molxMg/mol=7x129=> 903g