abc+ab+a = 259
ab•10+c+ab+a = 259
ab(10+1)+a+c = 259
ab•(11) = 259-(a+c)
ab = (259-(a+c))/11
Dacă a = 9, c = 9 => 259-18 = 241
11•21 = 231, 11×22 = 242, 11×23 = 253
=> ab = 23
=> 259-(a+c) = 253 => a+c = 6=>
Dar, a = 2 => c = 4, iar b = 3
=> a = 2, b = 3, c = 4
234+23+2 = 259
