[tex] \frac{1}{8} + \frac{1}{6 } + \frac{1}{2} = \frac{3}{24} + \frac{4}{24} + \frac{12}{24} = \frac{3 + 4 + 12}{24} = \frac{19}{24} [/tex]
[tex] \frac{1}{8} + \frac{1}{2} - \frac{1}{12} = \frac{3 + 12 - 2}{24} = \frac{13}{24} [/tex]
Am adus la acelasi numitor amplificand. succes!
