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Aduceti la o forma mai simpla expresia [tex]\frac{2-i}{3+i} +\frac{3+i}{2-1}[/tex]

Răspuns :

Explicație pas cu pas:

Atașament /_______________________/

Vezi imaginea SOS124

[tex]\dfrac{2-i}{3+i}+\dfrac{3+i}{2-i} = \dfrac{(2-i)(3-i)}{3^2-i^2}+\dfrac{(3+i)(2+i)}{2^2-i^2} = \\ \\ = \dfrac{6-2i-3i-1}{10}+\dfrac{6+5i-1}{5} = \dfrac{5-5i}{10}+\dfrac{5+5i}{5} = \\ \\ = \dfrac{1}{2}-\dfrac{1}{2}i+1+i = \boxed{\dfrac{3}{2}+\dfrac{1}{2}i}[/tex]