0.5+8•[1\4+(7\12-1\4)]:8 2\3=
=0.5+8•[1\4 amplificat cu 3+(7\12-1\4 anplificat cu 3)]:8 2\3=
=0.5+8•[3\12+(7\12-3\12)]:8 2\3=
=0.5+8•(3\12+4\12):8 2\3=
=0.5+8•7/12:8•12+7\12:26\3=
=0.5+103\12:26\3 amplificat cu 4=
=0.5+103\12:104\12=
=0.5+0.99\12=
=0.66
*sper ca te.am ajutat*