Răspuns:
Explicație pas cu pas:
a)2^6×5^6×2³=10^6×8=8000000
b)2^4×2^8×5³×5^6=10^9×2³=8000000000
c)2^6×3²×5^6=10^6×9=9000000
d)2^(1+2+3+4)×5^10:10^10=10^10:10&10=1
e) 2^(6+4+5)×5^(3+3+4+4+1):10^13=5^7×10^11:10^13=5^7:10²=5^5:4=3125/4
f)2^(3+4+7):2^(2+5+6)×5^5:5^4=2×5=10
a) (2^2)×(2^3)×(2^4)×(5^2)×(5^4)
(2^9)×(5^6) care apartine Naturaleleor(N)
b) (2^4)×(4^4)×125×(25^3)
(2^4)×[(2^2)^4]×(5^3)×[(5^2)^3]
(2^4)×(2^8)×(5^3)×(5^6)
(2^12)×(5^9) care apartine N
c) (2^1)×(2^2)×(2^3)×(3^2)×(5^6)
(2^9)×(3^2)×(5^6)
(2^9)×9×(5^6) care apartine N
d) (2^1)×(2^2)×(2^3)×(2^4)×(5^1)×(5^2)×(5^3)×(5^4)÷(10^10)=(2^10)×(5^10)×(10^10)=(2×5×10)^10=100^10 care apartine N.
e) 64×16×32×125×625×5÷10^13
(2^6)×(2^4)×(2^5)×(5^3)×(5^4)×5÷(2×5)13
(2^15)×(5^8)÷(2^13×5^13)
(2^2)×[5^(-5)]=4×[5^(-5}]=4×0,00032=0,0128
f)Nu mai am chef omule,scz dar m-am saturat sa iti calculez tie astea...!E extraordinar de simplu!
