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[tex]\lim_{x\to \11} ((x-1)/(x^2-1))[/tex]

Răspuns :

[tex]\lim_{x \to \11} \frac{x-1}{x^{2}-1 }= \lim_{x \to \11} \frac{x-1}{(x-1)*(x+1)}= \lim_{x \to \11} \frac{1}{x+1}=\frac{1}{1+1} = \frac{1}{2}[/tex]