Ecuația reacției de descompunere:
0.0975 x y
CaCO₃ ---(t°C)--> CaO + CO₂
1 1 1
Rezolvare:
[tex]m_{CaCO_3}=10\ g\\M_{CaCO_3}=40+12+(3{\cdot}16)=100\ g/mol\\2.5\%\ impur.\implies P=97.5\%\\\\P=\frac{m_p}{m_{imp}}{\cdot}100\implies\ m_{p}=\frac{P\ {\cdot}\ m_{imp}}{100}=\frac{97.5\ {\cdot}\ 10}{100}=9.75\ g\ CaCO_3\\\\n=\frac{m}{M}=\frac{9.75}{100}=0.0975\ moli\ CaCO_3[/tex]
[tex]n_{CaO}=x=0.0975\\M_{CaO}=40+16=56\ g/mol\\n=\frac{m}{M}\implies m=n\ {\cdot}\ M=0.0975\ {\cdot}\ 56=5.46\ g\ CaO\ (C_t)\\\\{\eta}=\frac{C_p}{C_t}{\cdot}100\implies C_p=\frac{{\eta}\ {\cdot}\ C_t}{100}=\frac{95\ {\cdot}\ 5.46}{100}=5.187\ g\ CaO[/tex]
[tex]n_{CO_2}=y=0.0975\ moli\\V_M=22.4\ dm^3\\n=\frac{V}{V_M}\implies V=n\ {\cdot}\ V_M=0.0975\ {\cdot}\ 22.4=2.184\ dm^3(L)\ CO_2[/tex]
