[tex]a = ( \frac{2}{3} - \frac{1}{2}) + \frac{3}{4} [/tex]
amplificam cu 4, 6 și 3
[tex]a = ( \frac{8}{12} - \frac{6}{12} ) + \frac{9}{12} \\ a = \frac{2}{12} + \frac{9}{12} \\ a = \frac{11}{12} [/tex]
[tex]b = \frac{5}{6} + (1 - \frac{3}{4} ) \\ b = \frac{10}{12} + ( \frac{12}{12} - \frac{9}{12} ) \\ b = \frac{10}{12} + \frac{3}{12 } \\ b = \frac{13}{12} [/tex]
[tex]c = \frac{1}{3} - ( \frac{5}{6} - \frac{1}{2} ) \\ c = \frac{4}{12} - ( \frac{10}{12} - \frac{6}{12} ) \\ c = \frac{4}{12} - \frac{4}{12} \\ c = \frac{0}{12} = 0[/tex]
[tex]d = 1 - ( \frac{2}{5} + \frac{1}{10} ) + \frac{3}{10} \\ d = \frac{10}{10} - ( \frac{4}{10} + \frac{1}{10} ) + \frac{3}{10} \\ d = \frac{10}{10} - \frac{5}{10} + \frac{3}{10} \\ d = \frac{5}{10} + \frac{3}{10} \\ d = \frac{8}{10} = \frac{4}{5} [/tex]
Fiecare numărător trebuie adus la un factor comun
